Extending MDS Codes

A q-ary (n, k)-MDS code, linear or not, satisfies n ≤ q + k − 1. A code meeting this bound is said to have maximum length. Using purely combinatorial methods we show that an MDS code with n = q + k − 2 can be uniquely extended to a maximum length code if and only if q is even. This result is best possible in the sense that there is, for example, a non-extendable 4-ary (5, 4)-MDS code. It may be that the proof of our result is as interesting as the result itself. We provide a simple necessary and sufficient condition \documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document}$$\left( {{\text{property }}\mathcal{P}} \right)$$\end{document} for code extendability. In future work, this condition might be suitably modified to give an extendability condition for arbitrary (shorter) MDS codes.