Effect of lid height and blowing ratio on film cooling effectiveness of a novel lidded hole configuration

被引:1
|
作者
Guelailia, Ahmed [1 ,2 ]
Khorsi, Azzeddine [2 ]
Slimane, Sid Ahmed [1 ,2 ]
Blala, Hamza [1 ]
Slimane, Abdelkader [2 ,3 ]
Salem, Houria [1 ]
Bouferrouk, Abdessalem [4 ]
机构
[1] Algerian Space Agcy ASAL, Space Mech Res Dept, Ctr Satellite Dev CDS, BP 4065 Ibn Rochd USTO, Oran, Algeria
[2] Univ Sci & Technol Mohamed Boudiaf, Fac Mech Engn, Lab Appl Mech, Oran, Algeria
[3] Univ Djilali Liabes, Dept Mech Engn, Lab Mat & React Syst, Sidi Bel Abbes, Algeria
[4] Univ West England, Dept Engn Design & Math, Bristol, Avon, England
关键词
Computational fluid dynamics; film cooling effectiveness; blowing ratio; heat and mass transfer; lidded hole; SINGLE ROUND HOLE; STREAMWISE ANGLES; CROSS-FLOW; PART I;
D O I
10.1177/09544089221095665
中图分类号
TH [机械、仪表工业];
学科分类号
0802 ;
摘要
Film cooling is one of the promising technologies used for protecting rocket nozzles and turbine blades from combustion chamber hot gases. This paper proposes a novel shape of film cooling injection hole, called lidded hole, that can offer significant enhancement of cooling performance. ANSYS CFX is used to perform 3D numerical simulations of a flat plate with a single row of lidded holes, in which the k-epsilon model approximates turbulence effects. Four cases are investigated to highlight the influence of the hole's lid height (H/d = 0, 0.25, 0.5, 0.75). The effect of blowing ratios (M = 0.5, 1, 1.5) is also analyzed for each configuration. The numerical results of this study are compared with available experimental data, and, generally, a good agreement is achieved. The results obtained show that the lidded hole configuration reduces the coolant flow separation which improves significantly the film cooling effectiveness. In addition, increasing the blowing ratio leads to an increase in lateral and centerline cooling effectiveness. Comparing all studied cases, the optimum coolant coverage was obtained for the lidded hole configuration with H/d = 0.25 at M = 1.5.
引用
收藏
页码:2599 / 2607
页数:9
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