A Diophantine equation related to the sum of powers of two consecutive generalized Fibonacci numbers

被引:5
|
作者
Chaves, Ana Paula [1 ]
Marques, Diego [2 ]
机构
[1] Univ Fed Goias, Inst Matemat & Estat, BR-74690612 Goiania, Go, Brazil
[2] Univ Brasilia, Dept Matemat, BR-70910900 Brasilia, DF, Brazil
关键词
Diophantine equations; Linear forms in logarithms; Generalized Fibonacci numbers; Reduction method;
D O I
10.1016/j.jnt.2015.03.009
中图分类号
O1 [数学];
学科分类号
0701 ; 070101 ;
摘要
Let (F-n) n >= 0 be the Fibonacci sequence given by Fm+2 = Fm+1 + F-m, for m >= 0, where F-0 = 0 and F-1 = 1. In 2011, Luca and Oyono proved that if F-m(s) + F-m+1(s) is a Fibonacci number, with m >= 2, then s = 1 or 2. A well-known generalization of the Fibonacci sequence, is the k-generalized Fibonacci sequence (F-n((k)))(n) which is defined by the initial values 0,0,..., 0,1 (k terms) and such that each term afterwards is the sum of the k preceding terms. In this paper, we generalize Luca and Oyono's method by proving that the Diophantine equation (F-m((k)))(s) + (F-m+1((k)))(s) = F-n((k)) has no solution in positive integers n,m,k and s, if 3 <= k <= min{m, log s}. (C) 2015 Published by Elsevier Inc.
引用
收藏
页码:1 / 14
页数:14
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