Can three bulky aryloxide substituents fit(~)around a single aluminum center? That this is indeed possible is shown by the product Al(OAr*)3 1 (Ar* = 2.6-tBu2-4-MeC6H2) of the reaction of HOAr* with LiAlH4. The Al-27{H-1} NMR spectrum and the X-ray structural analysis are in accord with a very electron-rich, three-coordinate aluminum center.