The authors prove that for arbitrarily given b∈(0,∞)\documentclass[12pt]{minimal}
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\begin{document}$$b\in (0,\infty )$$\end{document}, r∈(0,1)\documentclass[12pt]{minimal}
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\begin{document}$$r\in (0,1)$$\end{document} and n∈N0\documentclass[12pt]{minimal}
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\begin{document}$$n\in \mathbb {N}_0$$\end{document}, and for λ∈R\documentclass[12pt]{minimal}
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\begin{document}$$\lambda \in \mathbb {R}$$\end{document}, the functions a↦F(a,b;a+b;r)aλanda↦F(a,b;a+b;r)-∑k=0n(a,k)(b,k)(a+b,k)k!rkaλ\documentclass[12pt]{minimal}
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\begin{document}$$\begin{aligned} a\mapsto \frac{F(a,b;a+b;r)}{a^{\lambda }} \quad \text {and} \quad a\mapsto \frac{F(a,b;a+b;r) -\sum _{k=0}^n \frac{(a,k)(b,k)}{(a+b,k)k!}r^k}{a^{\lambda }} \end{aligned}$$\end{document}are both strictly increasing (decreasing) on (0,∞)\documentclass[12pt]{minimal}
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\begin{document}$$(0,\infty )$$\end{document} if and only if λ≤0\documentclass[12pt]{minimal}
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\begin{document}$$\lambda \le 0$$\end{document} (λ≥max{1,b}\documentclass[12pt]{minimal}
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\begin{document}$$\lambda \ge \max \{1,b\}$$\end{document}, respectively), where F(a,b;a+b;r)\documentclass[12pt]{minimal}
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\begin{document}$$F(a,b;a+b;r)$$\end{document} denotes the Gaussian hypergeometric function. This result gives one answer to an open problem raised by Qiu et al. (J Math Anal Appl 2020, 492(2):31, https://doi.org/10.1016/j.jmaa.2020.124469) recently.