Let R be a prime ring. Q its symmetric Martindale quotient ring. C its extended centroid, I a nonzero ideal of R and F a generalized derivation of R,m≥1,n≥1\documentclass[12pt]{minimal}
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\begin{document}$$R, m \ge 1, n \ge 1$$\end{document} two fixed integers and 0≠a∈R\documentclass[12pt]{minimal}
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\begin{document}$$0 \ne a \in R$$\end{document}. Assume that a((F(x∘y)m-(x∘y)n)=0\documentclass[12pt]{minimal}
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\begin{document}$$a((F(x \circ y)^m - (x\circ y)^n) = 0$$\end{document} for all x,y∈I\documentclass[12pt]{minimal}
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\begin{document}$$x,y \in I$$\end{document}. Then one of the following holds: R is commutative.n=m=1\documentclass[12pt]{minimal}
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\begin{document}$$n = m =1$$\end{document} and there exists b∈Q\documentclass[12pt]{minimal}
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\begin{document}$$b \in Q$$\end{document} such that F(x)=bx\documentclass[12pt]{minimal}
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\begin{document}$$F(x) = bx$$\end{document} for all x∈R\documentclass[12pt]{minimal}
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\begin{document}$$x \in R$$\end{document} with ab=a\documentclass[12pt]{minimal}
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\begin{document}$$ab = a$$\end{document}.There exists b∈C\documentclass[12pt]{minimal}
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\begin{document}$$b \in C$$\end{document} such that F(x)=bx\documentclass[12pt]{minimal}
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\begin{document}$$F(x) = bx$$\end{document} for all x∈R\documentclass[12pt]{minimal}
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\begin{document}$$x\in R$$\end{document} with bm=1\documentclass[12pt]{minimal}
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\begin{document}$$b^m = 1$$\end{document} and (x∘y)m=(x∘y)n\documentclass[12pt]{minimal}
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\begin{document}$$(x\circ y)^m = (x \circ y)^n$$\end{document}, for all x,y∈R\documentclass[12pt]{minimal}
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\begin{document}$$x,y \in R$$\end{document}.R⊆M2(C)\documentclass[12pt]{minimal}
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\begin{document}$$R \subseteq M_2(C)$$\end{document}, the ring of 2×2\documentclass[12pt]{minimal}
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\begin{document}$$2 \times 2$$\end{document} matrices over C,n=1\documentclass[12pt]{minimal}
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\begin{document}$$C, n=1$$\end{document} and m≥2\documentclass[12pt]{minimal}
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\begin{document}$$m \ge 2$$\end{document} such that αm=α\documentclass[12pt]{minimal}
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\begin{document}$$\alpha ^m =\alpha $$\end{document} for all α∈C\documentclass[12pt]{minimal}
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\begin{document}$$\alpha \in C$$\end{document}; and there exists b∈Q\documentclass[12pt]{minimal}
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\begin{document}$$b \in Q$$\end{document} such that F(x)=bx\documentclass[12pt]{minimal}
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\begin{document}$$F(x) = bx$$\end{document} for all x∈R\documentclass[12pt]{minimal}
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\begin{document}$$x \in R$$\end{document} with ab=a\documentclass[12pt]{minimal}
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\begin{document}$$ab = a$$\end{document}.R⊆M2(C)\documentclass[12pt]{minimal}
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\begin{document}$$R\subseteq M_2(C)$$\end{document} and char(R)=2\documentclass[12pt]{minimal}
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\begin{document}$$char(R) = 2$$\end{document}.Assume that char(R)≠2\documentclass[12pt]{minimal}
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\begin{document}$$char(R) \ne 2$$\end{document} and a((F(x∘y)m-(x∘y)n)∈Z(R)\documentclass[12pt]{minimal}
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\begin{document}$$a((F(x\circ y)^m - (x\circ y)^n) \in Z(R)$$\end{document} for all x,y∈I\documentclass[12pt]{minimal}
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\begin{document}$$x,y \in I$$\end{document}. If there exist x0,y0∈I\documentclass[12pt]{minimal}
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\begin{document}$$x_0, y_0 \in I$$\end{document} such that a((F(x0∘y0)m-(x0∘y0)n)≠0\documentclass[12pt]{minimal}
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\begin{document}$$a((F(x_0 \circ y_0)^m - (x_0 \circ y_0)^n ) \ne 0$$\end{document}, then either there exists a field E such that R⊆M2(E)\documentclass[12pt]{minimal}
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\begin{document}$$R \subseteq M_2(E) $$\end{document} or a∈Z(R),(x∘y)m-(x∘y)n∈Z(R)\documentclass[12pt]{minimal}
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\begin{document}$$a \in Z(R), (x\circ y)^m - (x\circ y)^n \in Z(R)$$\end{document} for any x,y∈R\documentclass[12pt]{minimal}
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\begin{document}$$x,y \in R$$\end{document} and there exist b∈Z(R)\documentclass[12pt]{minimal}
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\begin{document}$$b \in Z(R)$$\end{document} such that bm=1\documentclass[12pt]{minimal}
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\begin{document}$$b^m = 1$$\end{document}.