On the degree of univariate polynomials over the integers

被引:1
|
作者
Cohen, Gil [1 ]
Shpilka, Amir [2 ]
Tal, Avishay [3 ]
机构
[1] Princeton Univ, Dept Comp Sci, Princeton, NJ 08544 USA
[2] Tel Aviv Univ, Blavatnik Sch Comp Sci, IL-69978 Tel Aviv, Israel
[3] Inst Adv Study, Sch Math, Princeton, NJ 08540 USA
基金
以色列科学基金会;
关键词
DEPTH CIRCUITS;
D O I
10.1007/s00493-015-2987-0
中图分类号
O1 [数学];
学科分类号
0701 ; 070101 ;
摘要
We study the following problem raised by von zur Gathen and Roche [6]: What is the minimal degree of a nonconstant polynomial f: {0,..., n} -> {0,..., m}? Clearly, when m = n the function f(x) = x has degree 1. We prove that when m = n - 1 (i.e. the point {n} is not in the range), it must be the case that deg(f) = n - o(n). This shows an interesting threshold phenomenon. In fact, the same bound on the degree holds even when the image of the polynomial is any (strict) subset of {0,..., n}. Going back to the case m = n, as we noted the function f(x) = x is possible, however, we show that if one excludes all degree 1 polynomials then it must be the case that deg(f) = n - o(n). Moreover, the same conclusion holds even if m=O(n (1.475-I mu)). In other words, there are no polynomials of intermediate degrees that map {0,...,n} to {0,...,m}. Furthermore, we give a meaningful answer when m is a large polynomial, or even exponential, in n. Roughly, we show that if , for some constant c, and dae<currency>2n/15, then either deg(f) ae<currency> d-1 (e.g., is possible) or deg(f) ae<yen> n/3 - O(dlogn). So, again, no polynomial of intermediate degree exists for such m. We achieve this result by studying a discrete version of the problem of giving a lower bound on the minimal L (a) norm that a monic polynomial of degree d obtains on the interval [-1,1]. We complement these results by showing that for every integer k = O( ) there exists a polynomial f: {0,...,n}->{0,...,O(2 (k) )} of degree n/3-O(k)ae<currency>deg(f)ae<currency>n-k. Our proofs use a variety of techniques that we believe will find other applications as well. One technique shows how to handle a certain set of diophantine equations by working modulo a well chosen set of primes (i.e., a Boolean cube of primes). Another technique shows how to use lattice theory and Minkowski's theorem to prove the existence of a polynomial with a somewhat not too high and not too low degree, for example of degree n-Omega(logn) for m=n-1.
引用
收藏
页码:419 / 464
页数:46
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