QUANTUM PARRONDO'S GAMES CONSTRUCTED BY QUANTUM RANDOM WALKS

被引:12
|
作者
Li, Min [1 ,2 ]
Zhang, Yong-Sheng [1 ]
Guo, Guang-Can [1 ]
机构
[1] Univ Sci & Technol China, CAS, Key Lab Quantum Informat, Hefei 230026, Peoples R China
[2] XiaMen Univ Technol, Sch Optoelect & Commun Engn, Xiamen 361000, Peoples R China
来源
FLUCTUATION AND NOISE LETTERS | 2013年 / 12卷 / 04期
基金
中国国家自然科学基金;
关键词
Quantum random walks; Parrondo's games; quantum games;
D O I
10.1142/S0219477513500247
中图分类号
O1 [数学];
学科分类号
0701 ; 070101 ;
摘要
We construct a Parrondo's game using discrete-time quantum walks (DTQWs). Two losing games are represented by two different coin operators. By mixing the two coin operators U-A(alpha(A), beta(A), gamma(A)) and U-B(alpha(B), beta(B), gamma(B)), we may win the game. Here, we mix the two games in position instead of time. With a number of selections of the parameters, we can win the game with sequences ABB, ABBB, etc. If we set beta(A) = 45 degrees, gamma(A) = 0, alpha(B) = 0, beta(B) = 88 degrees, we find game 1 with U-A(S) = U-S(-51 degrees, 45 degrees, 0), U-B(S) = U-S(0, 88 degrees, -16 degrees) will win and get the most profit. If we set alpha(A) = 0, beta(A) = 45 degrees, alpha(B) = 0, beta(B) = 88 degrees and game 2 with U-A(S) = U-S(0, 45 degrees, -51 degrees), U-B(S) = U-S(0, 88 degrees, -67 degrees) will win most. Game 1 is equivalent to game 2 with changes in sequences and steps. But at large enough steps, the game will lose at last. Parrondo's paradox does not exist in classical situation with our model.
引用
收藏
页数:11
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