We show that shuffle, the problem of determining whether a string w can be composed from an order preserving shuffle of strings x and y, is not in AC(0), but it is in AC(1). The fact that shuffle is not in AC(0) is shown by a reduction of parity to shuffle and invoking the seminal result of Furst et al., while the fact that it is in AC(1) is implicit in the results of Mansfield. Together, the two results provide a lower and upper bound on the complexity of this combinatorial problem. We also explore an interesting relationship between graphs and the shuffle problem, namely what types of graphs can be represented with strings exhibiting the anti-Monge condition. (c) 2015 Elsevier B.V. All rights reserved.
机构:
Brown Univ, Dept English, Providence, RI 02912 USA
Brown Univ, Ctr Study Race & Ethn Amer, Providence, RI 02912 USABrown Univ, Dept English, Providence, RI 02912 USA